12x^2+7=5x^2+4x

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Solution for 12x^2+7=5x^2+4x equation: 



12x^2+7=5x^2+4x

We move all terms to the left:

12x^2+7-(5x^2+4x)=0

We get rid of parentheses

12x^2-5x^2-4x+7=0

We add all the numbers together, and all the variables

7x^2-4x+7=0

a = 7; b = -4; c = +7;
Δ = b2-4ac
Δ = -42-4·7·7
Δ = -180
Delta is less than zero, so there is no solution for the equation

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